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Opinionated
11-15-2007, 07:15 AM
I can't figure out how it's done, can you?
http://digicc.com/fido/
sorry, i'm a dummy :)

ck7684
11-15-2007, 07:18 AM
Nope, I cant... :idea:

Some Kind Of Monster
11-15-2007, 07:21 AM
I can't figure out how it's done, can you?
Amazing! :eek:

havaduner
11-15-2007, 07:27 AM
I'm stumped!:rolleyes:

phebus
11-15-2007, 07:28 AM
Smoke and mirrors :D

HM
11-15-2007, 07:28 AM
Bumble Bee Tuna

uvindex
11-15-2007, 07:34 AM
Shocking!

Cheap Thrills
11-15-2007, 07:35 AM
The mind is a terrible thing.
T.

Shreve"T"
11-15-2007, 07:35 AM
I give up !!!!!

Cigalert
11-15-2007, 07:52 AM
I think I got it....no wait...it's gone again.
That's my skull....I'm so wasted!

OCMerrill
11-15-2007, 08:34 AM
I don't see why it's so difficult? :eek:
:D

Moneypitt
11-15-2007, 08:40 AM
For $2.00 each I'll expalain it to you.........Send SASE..........MP

73kona455
11-15-2007, 08:54 AM
For $2.00 each I'll expalain it to you.........Send SASE..........MP
its easy.. and for $1.50 each i will explain it...:eek: :jawdrop: :D

BrianB
11-15-2007, 09:00 AM
Friggin amazing Bro....How does she fit it all in there?

Opinionated
11-15-2007, 09:50 AM
I added the link. sorry

Troy McClure
11-15-2007, 10:11 AM
The trick is: the remainder after division by nine equals the remainder of the sum of the digits after division by nine.
You start with any four digit number, with remainder x (when divided by nine). If you change the order of the digits, the sum of the digits doesn't change, and hence the remainder doesn't change. So if you subtract these two numbers, you'll end up with a number that is divisible by nine. This again means that the sum of the digits is divisible by nine. Now when you enter the three remaining digits, all that Fido has to do is find a fourth digit that completes the sum to be divisible by nine. Thus he substracts the sum of these three digits from the next larger multiple of nine to find the solution.
A worked out example:
8375
3587 -
------
4788 ( note that 4788 is divisible by 9, as is 4+7+8+8 = 27)
Suppose I circle one 8, and fill in '478' for Fido. He adds 4+7+8 = 19. The next larger multiple is 27. 27-19 equals 8, voila!
(By the way, there is one special case: if the sum of the three digits already is a multiple of nine, both the digits 0 and 9 are possible candidates. THAT is why you weren't allowed to circle a zero from the four numbers.)
But quite a nice 'trick' anyway, also because it works with any number of digits.
That solution was found here:
http://www.usenet.com/newsgroups/rec.puzzles/msg02576.html

BrianB
11-15-2007, 11:50 AM
Your Nerdism just leaked out:redface:

WaterJunky
11-15-2007, 01:21 PM
If you choose 9999 as your number it will not let you move past the number entry box. I found this out before reading the "how it works".
I guess I screwed that one up.....:confused:

Big Warlock
11-15-2007, 02:52 PM
The trick is: the remainder after division by nine equals the remainder of the sum of the digits after division by nine.
You start with any four digit number, with remainder x (when divided by nine). If you change the order of the digits, the sum of the digits doesn't change, and hence the remainder doesn't change. So if you subtract these two numbers, you'll end up with a number that is divisible by nine. This again means that the sum of the digits is divisible by nine. Now when you enter the three remaining digits, all that Fido has to do is find a fourth digit that completes the sum to be divisible by nine. Thus he substracts the sum of these three digits from the next larger multiple of nine to find the solution.
A worked out example:
8375
3587 -
------
4788 ( note that 4788 is divisible by 9, as is 4+7+8+8 = 27)
Suppose I circle one 8, and fill in '478' for Fido. He adds 4+7+8 = 19. The next larger multiple is 27. 27-19 equals 8, voila!
(By the way, there is one special case: if the sum of the three digits already is a multiple of nine, both the digits 0 and 9 are possible candidates. THAT is why you weren't allowed to circle a zero from the four numbers.)
But quite a nice 'trick' anyway, also because it works with any number of digits.
http://www.usenet.com/newsgroups/rec.puzzles/msg02576.html
well done!!!

No Name
11-15-2007, 02:56 PM
Your Nerdism just leaked out:redface:
:D :D

Troy McClure
11-15-2007, 06:26 PM
Your Nerdism just leaked out:redface:
Ha, Ha, no kidding. I can be a little geeky sometimes.
However, I can't take credit for the solution as I copied that from another site and listed the link at the bottom of my last post. Although I thought that I did, I did not specify that is where I found it. I will edit that post to do so...

wolfie
11-15-2007, 07:02 PM
doesn't work with the number 1111

YODA
11-15-2007, 07:33 PM
my answer is..........BOOBS !!!!!!!!!! Am I correct???